sexta-feira, 24 de outubro de 2025

Question: Analysis of Degree Correlations in Complex Networks

A network engineer is analyzing the topology of a large technological network. After data collection and a complete analysis, he calculated the Degree Correlation Coefficient rr for the network, obtaining the value: r=0.19.

The Degree Correlation Coefficient (rr) is defined as:

r  =  j,kjk(ejkqjqk)σr2r \;=\; \frac{\sum_{j,k} jk\,\bigl(e_{jk} - q_j q_k\bigr)}{\sigma_r^2}

where ejke_{jk} represents the probability of finding nodes with degrees jj and kk at the ends of a randomly selected edge; qkq_k is the probability that the end of an edge has degree kk(qk=kpk/k); and σr2\sigma_r^2 is the normalization term.

Based on this result (r=0.19r = -0.19) and on the theory of degree correlations, mark the correct statement about the topology of this network:

A) The value r=0.19r = -0.19 classifies the network as neutral. Neutral networks are those in which nodes connect to each other with the probabilities expected in random networks, implying that the difference j,kjk(ejkqjqk)\sum_{j,k} jk\,\bigl(e_{jk} - q_j q_k\bigr)is zero. The negative value obtained should be dismissed as a statistical artifact or a “structural cutoff”.

B) The value r=0.19r = -0.19 indicates that the network is disassortative. In disassortative networks, hub nodes tend to avoid linking to each other. This means that, for pairs of high-degree nodes (both jj and k large), the observed probability ejke_{jk} is lower than the expected probability qjqkq_j q_k of an uncorrelated network.

C) The negative value of rr points to an assortative network, since this type of network typically exhibits hubs connecting to low-degree nodes. The condition for rr to be positive (r0r \ge 0) is that the magnitude of the correlation captured by jkjk\langle jk\rangle - \langle j\rangle \langle k\rangle (the numerator of the formula) is positive.

D) Technological networks are classically assortative. The r=0.19r = -0.19 is atypical, but if it were truly disassortative, the impact would be increased robustness against targeted attacks, since removing a hub would not result in large cascades of disconnections among other hubs.

E) None of the above.


Original idea by: Matteus Vargas Simão da Silva

sábado, 4 de outubro de 2025

Question: Degree Dynamics in the BA Model

In the Barabási–Albert (BA) model, which incorporates growth (continuous addition of new nodes) and preferential attachment (new nodes prefer to connect to more connected nodes), the time evolution of a node’s degree, ki(t)k_i(t), is a central aspect.

The degree growth for a node ii, which entered the network at time tit_i with mm links, follows a power law in time tt, characterized by the dynamic exponent β\beta.

Which of the following formulas correctly represents the degree growth law ki(t)k_i(t) for a node ii in the BA model?

A.

ki(t)=m(tti)1/2k_i(t) = m \left( \frac{t}{t_i} \right)^{1/2}

B.

ki(t)=mttik_i(t) = m \frac{t}{t_i}

C.

ki(t)=kγwhereγ=3k_i(t) = k^{-\gamma} \quad \text{where} \quad \gamma = 3

D.

ki(t)=m(tti)2k_i(t) = m \left( \frac{t}{t_i} \right)^{2}

E. None of the above


Original idea by: Matteus Vargas Simão da Silva

Network Robustness

Using the giant-component breakdown criterion, ⟨ k ′ 2 ⟩ f ⟨ k ′ ⟩ f = 2 \frac{\langle k'^2 \rangle_f}{\langle k' \rangle_f} = 2 , a...